I'm new to this area and recently, for a college job I could not turn that line of code into a tuple. function code:
def encontra_impares(lista):
lis = []
if len(lista) > 0:
numero = lista.pop(0)
if numero % 2 != 0:
lis.append(numero)
lis = lis + encontra_impares(lista)
return lis
function call:
print(encontra_impares([1, 2, 3,5,5,9,7,32,1,6]))
You can adjust your function to something like:
def encontra_impares( tupla ):
lista = []
for n in tupla:
if n % 2 != 0:
lista.append(n)
return lista
tpl = (1, 2, 3,5,5,9,7,32,1,6)
lst = encontra_impares( tpl )
print(tpl)
print(lst)
Or Simply:
def encontra_impares( tupla ):
return [ n for n in tupla if n % 2 != 0 ]
tpl = (1, 2, 3,5,5,9,7,32,1,6)
lst = encontra_impares( tpl )
print(tpl)
print(lst)
Output:
(1, 2, 3, 5, 5, 9, 7, 32, 1, 6)
[1, 3, 5, 5, 9, 7, 1]
Dude I was a bit confused with what exactly you want but according to your goal would do it this way:
lis=[]
lista=[0,1,2,3,4,5,6,8,9]
for i in range(len(lista)):
if lista[i]%2 == 0:
lis.append(lista[i])