How do I use preg_match to detect a string where it has to start with "/ command"?
This function, for me, is very complicated to understand ...
I wanted to detect a / command at the beginning of a sentence and get the rest of the string to continue the command
For example:
/ talk test1 test2 test3
Detect the "/ talk" command and say "test1 test2 test3"
Hello, if your variable that contains the sentence ALWAYS start with "/", I say, for example, if the / command is not from the 4th character, you can do this with the function strpos .
A working example would be:
$var_texto = "/comando teste1 teste2 teste3";
// retorna true se $var_texto começar com /
if(strpos($var_texto, "/") === 0){
$array_texto = explode(" ", $var_texto);
$comando = $array_texto[0];
// Remove o comando dos arrays
unset($array_texto[0]);
// Obtem a string final
$continuacao = implode(' ', $array_texto);
}
This way you will have the command is $comando and its parameters are in $continuacao
You can also use preg_match_all :
$var_texto = "/comando teste1 teste2 teste3";
if(preg_match_all('/(\/\w+)|(\w+\s\w).*/', $var_texto, $matches)) {
echo $matches[0][0], PHP_EOL; // -> /comando
echo $matches[0][1], PHP_EOL; // -> teste1 teste2 teste3
} else {
echo 'Fora do padrão', PHP_EOL;
}
Regex:
(\/\w+) -> captura a barra "/" e caracteres alfanuméricos até um espaço
(\w+\s\w).* -> captura caracteres alfanuméricos separados por espaço, tudo junto