I'm having a problem with a list.
I have a txt with some information (log failure of a system) and I wanted python to print to me these faults with the "translation" of them example:
If cod_erro == '1': print ('Invalid password')
and so on ... follow the code:
# -*- coding: utf-8 -*-
row = []
li = []
x = 0
y = 0
count = []
with open("Txts/test3.txt", "r") as arq:
for linha in arq:
if linha.find('Failed') > -1:
li += linha.split(': ') #li recebe todos os valores separados pelo split ou seja li vai ter o valor anterior + o novo valor gerando assim uma lista conforme o numero de palavras que tem no texto
li = [item.replace("\n", "") for item in li]
y = len(li)
#print(li[x]) #colocar [x] x = numero para printar o valor especifico
while x != y :
#print('oi') #teste pra ver se ia executar a quanitdade de vezes correta
print(li[x]) #Teste pra ver se iria printar os valores alocados
if li[x] == '1':
print('Apenas um teste')
break
x = x + 1
My problem is that Python does not appear to be entering the IF condition (if I start li [1] the value will be '1' but if it does not work with those values)
BUT ALL THE WAY AND BETWEEN: if I put it that way if li [x] == 'Failure' it goes into condition .....
@@ EDIT: The if does not work when the error returned is a number, if it is a letter it works normally