Good evening people, as I can do, to pick up the 1st day of each month, counting the beginning of today's date, and taking the next day 01/08/2018 and the next 12 months.
Try this code:
$firstDayNextMonth = date('Y-m-d', strtotime('first day of next month'));
How would you get the next 12?
If you use DateTime to get one month at a time in a loop I use ::modify() you can extract, for example:
<?php
$dt = new DateTime('first day of next month');
$datas = array( $dt->format('Y-m-d') );
for ($i = 0; $i < 12; $i++) {
$dt->modify('+1 month');
$datas[] = $dt->format('Y-m-d');
}
print_r($datas);
Result:
Array ( [0] => 2018-08-01 [1] => 2018-09-01 [2] => 2018-10-01 [3] => 2018-11-01 [4] => 2018-12-01 [5] => 2019-01-01 [6] => 2019-02-01 [7] => 2019-03-01 [8] => 2019-04-01 [9] => 2019-05-01 [10] => 2019-06-01 [11] => 2019-07-01 [12] => 2019-08-01 )
This will actually take 13 months, since we started with the first month, since you said:
and catching the next day 08/01/2018 and the next 12 months.
But if you want to get it from the next month count the 12 months then change it to 11 for :
for ($i = 0; $i < 11; $i++) {
Although I do not think I would need this, after all, if it's the first day, just enumerate an array by adding the month, when it goes from 12 to month 1 and adds the year:
<?php
$j = count($meses);
$ano = date('Y');
$mes = date('m');
$datas = array();
for ($i = 0; $i < 12; $i++) {
$mes++;
if ($mes > 12) {
$mes = 1;
$ano++;
}
$datas[] = sprintf('%04d-%02d-01', $ano, $mes);
}
print_r($datas);