I need to do a recursive function in python to return the number of the inverted form, but to be converted to string.
I just managed to do it this way:
import math
def inverte(num):
if(num < 10):
return num
q=num//10
q=inverte(q)
r=num%10
inv=r*10**((math.floor(math.log10(q)+1)))+q
return inv
print(inverte(1234))
However, my teacher said that I could do just using whole division and rest. Does anyone help?
A simple solution, but a rather boring logic to solve. Here is a way to solve this using integer division and recursion, without the conversion to other types:
def inverte(num, aux=0):
if num < 10:
return aux + num
aux = aux * 10 + num % 10 * 10
return inverte(num // 10, aux)
In Python, the // operator functions as a floor division (or entire division as mentioned by your teacher).
I hope to have helped, any further questions feel free to contact.