I would like to know how to format the variable:
local n = 100000000
To return like this:
100.000.000
Separated by dots, does anyone know how to do it?
How to format numbers in Lua?
5
asked by anonymous 04.06.2015 / 04:46
3 answers
3
function dot_string(s)
-- não precisamos de pontinhos para números até 999
if s:len() <= 3 then
return s
end
-- senão, colocamos o pontinho no último grupo de 3 e repetimos o processo para o que sobrou
return dot_string(s:sub(1, -4)) .. "." .. s:sub(-3)
end
function dot_number(n)
-- TODO: n < 0
-- TODO: n != int(n)
-- TODO: n grande
return dot_string(tostring(n))
end
If on is negative, fractional or giant, tostring () will do lame, but otherwise the function does what you asked for (at least the first two cases are easy to handle with if s in dot_number before call the dot_string).
Example:
print(dot_number(0))
print(dot_number(10))
print(dot_number(210))
print(dot_number(3210))
print(dot_number(43210))
print(dot_number(543210))
print(dot_number(6543210))
print(dot_number(10000000000000))
print()
-- …alguns casos que não funcionam…
print(dot_number(-123))
print(dot_number(12.5))
print(dot_number(100000000000000))
Output:
0
10
210
3.210
43.210
543.210
6.543.210
10.000.000.000.000
-.123
1.2.5
1e.+14
04.06.2015 / 12:00
4
The form proposed by page Formatting Numbers - lua-users.org is to use the string.gsub function as follows:
function formatarNumero(valor)
local formatado = valor
while true do
-- O "." entre "%1" e "%2" é o separador
formatado, n = string.gsub(formatado, "^(-?%d+)(%d%d%d)", '%1.%2')
if ( n ==0 ) then
break
end
end
return formatado
end
04.06.2015 / 13:03
0
function func(number)
local number = number
local decimal = number - math.floor(number)
decimal = tonumber(tostring(decimal):sub(3, string.len(decimal)))
number = tostring(math.floor(number)):reverse()
for _ = 3, #number, 4 do
number = number:sub(1, _) .. "." .. number:sub(_ + 1, #number)
end
return number:reverse() .. (decimal and "," .. decimal or "")
end
27.06.2015 / 03:59