Passing $ _POST by URL

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Passing $ _POST by URL

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#1 by (2 votes)

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I have a form that is dynamically mounted according to the preferences of each user and is submitted via post to the page that makes the process.

On the process page I need, among other things, to load an iframe that will bring in extra information, according to the information in the dynamic form of the first screen.

My problem is right there: how do I pass the information to the iframe to bring in the extra information?

Example: Form

<form method="post" action="processa.php">

   <label>Ano</label>
   <div>
      <select id="ano" name="ano">
         <option value="0">2000</option>
         <option value="1">2001</option>
         <option value="2">2002</option>
      </select>                     
   </div>

   <label>Mes</label>
   <div>
      <input type="text" id="mes" name="mes">                     
   </div>

   <label>Dia</label>
   <div>
      <input type="text" id="dia" name="dia">                    
   </div>

</form>

Example: Page that processes

<?php
   $_SESSION["pesquisa"] = $_POST; //ERRO POIS $_POST RETORNA ARRAY
   $_SESSION["pesquisa"] = implode("&",$_POST); //NAO SERVE POIS FICA 2000&03&12
?>

<script>
   parent.iframe.location.href = 'mais_infos.php?<?php echo $_SESSION["pesquisa"];?>';
</script>

I would need my $_SESSION["pesquisa"] to be something like ano=2000&mes=03&dia=12 to be able to complete the URL, but remembering again, the form fields are mounted dynamically.

php url post

asked by anonymous 12.06.2015 / 14:44

1 answer

Capture information and use when you need Java C - Concatenate char (Not STRCAT)

score 2 · Accepted Answer

What I understand is what you need to pass data from a form to the iframe dynamically. As the data comes via POST, it would soon come in the format $_POST['nome_campo'] = valor . If you make a

$variavel = '';
foreach ($arrayPost as $campo => $valor){
    if (end($arrayPost) != $valor)
        $variavel .= $campo.'='.$valor.'&';
    else
        $variavel .= $campo.'='.$valor;
}

Make sure that the variable $variavel returns exactly what you want.