Within my arquivo.txt file I keep two strings "nome" and "senha" , they stay one below the other.
I need to get the name and password entered by the user and compare it with the name and password I have saved in the .txt file
I made a while , so that enquanto for diferente de EOF , it rotates ...
Since I did not find a way to compare the typed variables to those in the file, I called strcpy .
I created two more char variables and copied the nome and senha that were typed by the user to string2 and string3 . So that I can then compare nome with string2 and senha with string3 .
But there is always a warning that I can not understand.
warning: format '%s' expects argument of type 'char' *', but argument 3 has type 'char'(*)[100]'
I understand what is written, but I do not understand what that interferes with the code.
The error you give in the program is as follows: Everything I type, it enters as true, it enters the if and prints Welcome!
FILE *fp;
fp = fopen("arquivo.txt", "r");
if (fp == NULL) {
printf("\nO arquivo não foi aberto!");
exit(0);
}
char nome[100], senha[100], string2[100],string3[100];
printf("\n\tNOME........: ");
scanf("%s", nome);
//Tentei fazer com fgets, mas da erro quando uso no while, então
//resolvi deixar o scanf mesmo
printf("\n\tSENHA........: ");
scanf("%s", senha);
printf("\n");
// printf("\n%s %s", nome, senha); //testar o que foi digitado pelo usuario
printf("\n");
while( (fscanf(fp, "%s %s", &nome, &senha)) != EOF ) {
strcpy(string2, nome);
strcpy(string3, senha);
if ( (strcmp(nome, string2) == 0) && (strcmp(senha, string3) == 0) ) {
printf("\nBem-Vindo!\n");
} else {
printf("\nSeu login ou senha estão errados!");
}
}
}
fclose(fp);
}