Evaluative activity hours per minute

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Evaluative activity hours per minute

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#1 by (2 votes)

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Question (2): Make a program that receives an hour consisting of hour and minutes (a real number), calculate and show the time entered in minutes. Consider that:


For four-thirty (4:30), enter 4.30;

For four and fifty (4:50), you must type 4.50;

Minutes range from 0 to 59

What I tried to do:

#include<math.h>
#include<stdio.h>
#include<stdlib.h>
#include<locale.h>

int main(){
    setlocale(LC_ALL, "portuguese");
    float hora, min;


        printf("Insira as horas formatada 0.00: ");
        scanf("%f", &hora);

        min = hora;

            hora = (hora * 60);
            min = (min * 100)%100;
            hora = hora + min;

        printf("%2.0f minutos", hora);



}

But this error always appears:

C: \ Users \ Lelre \ Desktop \ ASSESSMENT ACTIVITY 2.c | 17 | error: invalid operands to binary% (have 'float' and 'int') |

I can not use mod with float values but is there any way to transform float to integer to get the remainder of the division and add to the minutes?

c float

asked by anonymous 07.04.2017 / 17:03

1 answer

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score 2 · Answer 1

I think this is what you want.

#include<stdio.h>

int main() {
    float hora;
    printf("Insira as horas formatada 0.00: ");
    scanf("%f", &hora);
    float min = hora;
    hora = (int)hora;
    min = (min - hora) * 100;
    hora = hora * 60 + min;
    printf("%2.0f minutos", hora);
}

See running on ideone . And at Coding Ground . Also put it on GitHub for future reference .