Well I have the following json:
{
"Autenticacao": [{
"login": "teste",
"token": "100",
"senha": "123"
}]
}
I get this Json like this:
// Recebe JSON
$json = filter_input(INPUT_POST, 'json', FILTER_DEFAULT);
// Decodifica json
$jsonObj = json_decode($json);
How do you check if json has the key Autenticacao ?
You can use the array_key_exist function but for this you need to inform the json_decode to convert json to array and not objeto , or use the function property_exists to test objeto .
Verify with objeto :
$raw = '{"Autenticacao": [{"login": "teste","token": "100","senha": "123"}]}';
$jsonData = json_decode($raw);
// Segundo parametro define que a conversão sera para array
var_dump(property_exists($jsonData, 'Autenticacao'));
// Saida: true
Verify with conversion to array :
$raw = '{"Autenticacao": [{"login": "teste","token": "100","senha": "123"}]}';
$jsonData = json_decode($raw, true);
// Segundo parametro define que a conversão sera para array
var_dump(array_key_exists('Autenticacao', $jsonData));
// Saida: true
Data validation from POST
According to the documentation , the function filter_input will have the following return;
Returned
Value of the requested variable on success, FALSE if the filter fails, or NULL if the parameter variable_name is an undefined variable. If the FILTER_NULL_ON_FAILURE flag is used, it returns FALSE if the variable is not set and NULL if the filter fails.
Knowing said validation can only be done with a if
// $json = filter_input(INPUT_POST, 'json', FILTER_DEFAULT);
// o filtro FILTER_DEFAULT já é aplicado por padrão então ele pode ser removido
$json = filter_input(INPUT_POST, 'json', FILTER_NULL_ON_FAILURE);
// A variavel $json contera o valor da variavel ou NULL/FALSE em caso de erro.
if ($json) { ...
When you make a $jsonObj = json_decode($json) , PHP already turns $ json into an array, so you can do a simple logic test like if(isset($jsonObj['Autenticacao']))