I have the following code:
At the command line
> teste.py primeiro segundo
In the script teste.py :
import sys
print(sys.argv)
And I have the following return:
['c:\teste.py', 'primeiro', 'segundo']
But I would like to remove the first element.
What are the possible ways to remove the first from a list in Python ?
You can also use the del method to remove a item specifying your index.
lista = ['foo', 'bar', 'baz']
del lista[0]
print lista # ['bar', 'baz']
The difference between pop and del is that pop returns the removed value, while del only removes.
See an example:
lista1 = ['foo', 'bar', 'baz']
lista2 = ['aaa', 'bbb', 'ccc', 'ddd']
del lista1[0]
deleted = lista2.pop(0)
print (lista1) # ['bar', 'baz']
print (lista2) # ['bbb', 'ccc', 'ddd']
print ("O valor %s foi deletado da lista1" % deleted) # O valor aaa foi deletado da lista1
There is also the remove() method that, instead of specifying the index, is used to remove it from the list.
lista = ['foo', 'bar', 'baz']
lista.remove('foo')
print lista # ['bar', 'baz']
The remove method will remove the first matching value, assuming that the list has two equal values, only the first value will be removed.
Use the pop method, documentation here :
lista = sys.argv
lista.pop(0)
Another way would be to get the items from the second item in the list:
>>> a = [a, b, c, d, e, f]
>>> a = a[1:]
[b, c, d, e, f]