Separate strings by semicolons but also save semicolons

After reading a few times, I think I understand what you're looking for:

  

Separate a string using space (""), line break (\ n or \ r) and semicolon (;) as delimiters, but including ; as a list item.

If it is correct, I was able to combine a regex that meets these conditions, and the result was:

String[] stringSeparada = teste.split("((?<=;)|(?=;))|\s");

See the test below:

//dois exemplos com ambos os tipos de quebras de linhas(windows/linux)
String teste = ";espaco pontoevirgula;QUEBRA\ndelinha;";
String teste2 = ";espaco pontoevirgula;QUEBRA\rdelinha;";
String regex = "((?<=;)|(?=;))|\s";

String[] stringSeparada = teste.split(regex);
String[] stringSeparada2 = teste2.split(regex);

System.out.println(Arrays.toString(stringSeparada));
System.out.println(Arrays.toString(stringSeparada2));

Output:

  

[;, space, dot-line,;, BREAK, deline,;]
  [;, space, point, point,;, BREAK, deline,;]

Note that regex will capture ; regardless of where it appears.

See working online at IDEONE .

References:

• How can I split the string in Java and retain the delimiters?
• How to split a string, but also keep the delimiters?
• Java Regex Doc (Class Pattern)