I have the following code, the problem is that it returns string2 as '(null)'. How do I solve it? and why does this happen?
#include <stdio.h>
int main()
{
char *string;
char *string2;
printf("Primeiro nome: ");
scanf("%s", string);
printf("Ultimo sobrenome: ");
scanf("%s", string2);
printf("Ola senhor %s %s. Bem-vindo.\n", string, string2);
return 0;
}
Experiment with arrays instead of pointers
#include <stdio.h>
int main(void)
{
char string[1000]; // array em vez de ponteiro
char string2[1000]; // array em vez de ponteiro
printf("Primeiro nome: ");
if (scanf("%999s", string) != 1) /* erro */;
printf("Ultimo sobrenome: ");
if (scanf("%999s", string2) != 1) /* erro */;
printf("Ola senhor %s %s. Bem-vindo.\n", string, string2);
return 0;
}
If you really want to use pointers, you have to allocate space for the strings, and release that space when it is no longer necessary:
#include <stdio.h>
#include <stdlib.h> /* malloc() and friends */
int main(void)
{
char *string;
char *string2;
string = malloc(1000); /* aloca espaco */
if (string == NULL) /* erro */;
string2 = malloc(1000); /* aloca espaco */
if (string2 == NULL) /* erro */;
printf("Primeiro nome: ");
if (scanf("%999s", string) != 1) /* erro */;
printf("Ultimo sobrenome: ");
if (scanf("%999s", string2) != 1) /* erro */;
printf("Ola senhor %s %s. Bem-vindo.\n", string, string2);
free(string); /* liberta espaco */
free(string2); /* liberta espaco */
return 0;
}