I can not display the first 5 divisibles by 3, I put a counter variable, but it returns another number.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n = 20;
for(int i=1; i<=n; i++) {
if(i%3 == 0)
printf("%d\n", i);
}
return 0;
}
Could someone explain me how?
To display the first 5 numbers just count the number of numbers divisible by 3, when the number equals 5 closes the loop, see the example:
#include <stdio.h>
int main(void)
{
int cont = 0, numero = 0;
while (1)
{
numero++;
if (numero % 3 == 0)
{
printf("%d\n", numero);
cont++;
}
if (cont == 5)
break;
}
return 0;
}
Output:
3
6
9 12 15
You need to use a flag to check if you have already printed all 5 first numbers.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n = 20;
int flag = 0;
for(int i=1; i<=n; i++) {
if(i%3 == 0) {
flag++;
printf("%d\n", i);
if(flag == 5)
return 0;
}
}
return 0;
}