I have an a.txt file that inside it has adsaadv I would like to look in addition to other files starting with a and ending with v.
I thought of using the grep something like, grep "^ [a-v $]" a.txt
However, I did not succeed, do I have to merge grep commands with something else?
Thank you if you can give me a clairvoyance.
ls | grep ^a.*v$
ls lists directory | o pipe sends the output of ls to grep
grep filters the input with a regular expression, and returns on output by default ^ is the beginning of the line a is the character at the beginning of the line .* the dot means "any character". The asterisk means "how many characters are there" v is the character you want at the end $ is the end of the line As you want the extension, set to:
ls | grep ^a.*v\.txt$
\ means that the next point is a point of fact, not a RegEx joker.
Neither does it need to complicate so much; the old ls command can help you with this very easily.
Just make one:
ls a * v
But you have misunderstood the question, because it looks for a certain combination of text within a file, so to solve your problem, make one:
grep [^ a]. [v $] a.txt