I'm doing a script that needs the IP of the machine on the network, tried in many ways without success until I discovered a way:
ip="'ip addr show | grep global | grep -oE '((1?[0-9][0-9]?|2[0-4][0-9]|25[0-5])\.){3}(1?[0-9][0-9]?|2[0-4][0-9]|25[0-5])' | sed -n '1p''"
echo $ip
It worked, but it seems to me a very dirty method. Is there any other way to do this?
Remembering that the same machine can have multiple addresses of IP . The solutions proposed here apply to machines Linux and return only the address of IP primary:
1) Using hostname + cut :
$ hostname -I | cut -f1 -d' '
2) Using hostname + awk :
$ hostname -I | awk '{print $1}'
3) Using ifconfig + grep :
$ ifconfig | grep -Eo 'inet (addr:)?([0-9]*\.){3}[0-9]*' | grep -Eo '([0-9]*\.){3}[0-9]*' | grep -v '127.0.0.1'
Another option
: ~ $ hostname -I
192.168.1.105 172.17.0.1