I programmed my controller as follows:
[HttpPost]
public ActionResult Login(string pUsuario, string pSenha)
{
usuario oUsuario = modelOff.usuarios.Where(p => p.usuario1 == pUsuario && p.senha == pSenha).SingleOrDefault();
if (oUsuario == null)
return View("nao");
else
return View(oUsuario.usuario1);
}
I want to know how to display this information in view .
My view :
@{
ViewBag.Title = "Login";
}
<h2>Olá Fulano</h2>
Hello, There are several ways to pass data to View one of them is this:
ViewBagisavariablethatloadsinformationtoview,andMessageisakeywhereyouwillputavalue,thatis,youcancreateothernamesasinthisexamplehere:
ThereisalsoavariablecalledViewDatathathasthesamepurpose,thisistypedasadictionarycontainingobjects,intheexamplebelowwecanseeinmoredetail:
There are other ways to pass data, but I think the ones I mentioned solve your problem.
For your case, a simple viewBag should probably serve:
[HttpPost]
public ActionResult Login(string pUsuario, string pSenha) {
usuario oUsuario = modelOff.usuarios.Where(p => p.usuario1 == pUsuario && p.senha == pSenha).SingleOrDefault();
ViewBag.usuario = oUsuario == null ? "nao" : oUsuario.usuario1;
return View();
}
View:
//precisa colocar onde está o modelo aqui, mas na pergunta não tem a localização
@{
ViewBag.Title = "Login";
}
<h2>Olá Fulano @ViewBag.usuario</h2>
You can also do it differently:
[HttpPost]
public ActionResult Login(string pUsuario, string pSenha) {
usuario oUsuario = modelOff.usuarios.Where(p => p.usuario1 == pUsuario && p.senha == pSenha).SingleOrDefault();
ViewBag.usuario = oUsuario == null ? "nao" : oUsuario.usuario1;
return View((object)(oUsuario == null ? "nao" : oUsuario.usuario1));
}
View:
@model string
@{
ViewBag.Title = "Login";
}
<h2>Olá Fulano @Model</h2>
There are other ways.