What is the difference in percentage numbers of the ip possibilities of IPv4
and IPv6
?
What is the difference in percentage numbers of the ip possibilities of IPv4
and IPv6
?
As already mentioned, IPV6
uses 128-bit addresses and therefore has 2 128 numbers of IP
possible, that is:
340282366920938463463374607431768211456 Possible combinations.
(340 undecons) 282 deciles 366 nonillions 920 octillions 938 setirons 463 sextilons 463 quintillions 374 quadrillion 607 trillion 431 billion 768 million 211 thousand 456)
While IPV4
uses 32-bit addresses and has 2 32 numbers of IP
possible, corresponding to:
4294967296 possible combinations
(4 billion 294 million 967 thousand 296)
That is, it is a very, very, very high number.
While in IPV4
template we have something similar to this:
192.168.0.1
4 groups with up to 3 decimal digits.
So, for each set of 3 digits we have:
2 8 * 2 8 * 2 8 32
2 8 = 256. 2 32 = 4294967296
No IPV6
has IP
this way:
2001: 0db8: 85a3: 08d3: 1319: 8a2e: 0370: 7344
Eight groups of 4 hexadecimal digits.
This difference in notation has enabled a greater range of possibilities, which can be calculated as follows:
2 16 * 2 16 * 2 16 / sup> * 2 16 * 2 16 * 2 16 ) = 2 128 >
because the hexadecimal numbers comprise 16 values from 0 to 9 and from A to F then 2 128 matches the 340282366920938463463374607431768211456 mentioned above.
With a simple 3 rule we have to:
2 128 = 100%
2 32 = x2 128 x = 2 32
x
x = 1/79228162514264337593543950336
That is,IPV6
is 79.228.162.514.264.337.593.543.950.336% greater thanIPV4
AndIPV4
has:1.262177448353618888658765704452457967477130296174436807 ... × 10 -29 % of the
IPV6
addresses
Free translation of Wikipedia content in English :
IPv6 uses 128-bit addresses, allowing 2 128 or 3.4 × 10 38 addresses, that is, more than 7.9 × 10 28 times more than IPv4.
This means, according to the comments posted below by @Vargas and @tsippert:
IPv4 has 32 bits, IPV6 has 128 bits.
It is so absurdly large that it is possible to say that IPV4 = 0% of IPV6