Not understanding what happened:
ready = function() {
groups = mongoose.model('groups', schemas.group);
groups.find({}, function(err, docs){
for(i in docs){
console.log(docs[i].name);
}
return docs;
});
}
console.log(ready());
OUTPUT:
undefined
Grupo A
Grupo B
Grupo C
was not it for him to print as in function? If someone can help me, I appreciate it.
As far as I can tell from your code, the .find() method is asynchronous. So you have to use a callback to get those results. The logic may look like this:
var ready = function(callback) {
groups = mongoose.model('groups', schemas.group);
groups.find({}, callback);
}
and then you call the function ready passing as an argument the function that will be called when the data is ready:
ready(function(err, docs){
for(i in docs){
console.log(docs[i].name);
}
// fazer algo com os dados aqui...
});
That is, you can not use the usual sequence logic JavaScript sync, but a callback logic. You can read more about this here (link) .