Program does not execute without reading the contents of the variable

Question

Program does not execute without reading the contents of the variable

Navigation

#1 by (0 votes)

1

I'm creating a simple program for a college job, which reads 2 numbers, an arithmetic operator and returns the result of that operation. But it happens that after printing on the screen "enter the operator", the program does not expect me to enter the character, but ends the program soon. What is wrong? follow the code.

#include <stdio.h>
int main() {
    float n1,n2;
    char op;

    printf("Digite o primeiro operando: \n");
    scanf("%f", &n1);

    printf("Digite o segundo operando: \n");
    scanf("%f", &n2);

    printf("Digite um dos operadores aritmeticos (+,-,* ou /): \n");
    scanf("%c", &op);

    if (op == '+')
      printf("%f, %c",n1,op,n2,"=",n1+n2);
    else if (op == '-')
       printf("%f, %c",n1,op,n2,"=",n1-n2);
    else if (op == '*')
        printf("%f, %c",n1,op,n2,"=",n1*n2);
    else if (op == '/') {
        while (n2=0) {
            printf("Digite o divisor não nulo: \n");
            scanf("%f", &n2);
        }
        printf("%f, %c",n1,op,n2,"=",n1/n2);
    }
    else
        printf("Operador invalido! \n");

    return 0;             
}

c

asked by anonymous 25.02.2017 / 17:09

1 answer

How to calculate a value while the user types in an Android application? AttributeError: 'list' object has no attribute 'apend'

score 0 · Accepted Answer

Cauã, what I did to solve your problem, was to put a blank before %c

printf("Digite um dos operadores aritmeticos (+,-,* ou /):\n");
scanf(" %c", &op);

You do not need to use white space, so you can use fflush

fflush(stdin);      
printf("Digite um dos operadores aritmeticos (+,-,* ou /):\n"); 
scanf("%c", &op);