With expression [\d]{9} I can identify numeric characters if they are repeated nine times in sequence, however I only want identify if they are the same characters, for example:
111111111 // false
222222222 // false
333333333 // false
077546997 // true
123566566 // true
How should this grouping be handled?
You can use this way: (?!(\d){8})\d{9}
Basically two parts:
(?!(\d){8})
\d{9}
The negative look ahead part of the (?! .... ) tag looks for strings that should not be accepted. Well, make a catch group and then use that catch as a reference with as I explained in this other response . Basically it takes the first number and says that it must have 8x the same number (within this deny field).
You can use the (\d){8} expression.
Where:
(\d) : Capture group, only 0-9 digits. {8} : Refers to the first catch group. It will correspond to the same pattern matched by the catch group, eight times. See more details here .
console.log(/(\d){8}/.test('111111111'));
console.log(/(\d){8}/.test('222222222'));
console.log(/(\d){8}/.test('333333333'));
console.log(/(\d){8}/.test('444444444'));
console.log(/(\d){8}/.test('077546997'));The expression used in the response will match the numbers repeated in sequence, to do the opposite, see @Sergio and @Allan !
One option is to use the regular expression below and deny its output:
0{9}|1{9}|2{9}|3{9}|4{9}|5{9}|6{9}|7{9}|8{9}|9{9}
Result:
111111111 // home
222222222 // home
333333333 // home
077546997 // not home
123566566 // not home