I need to get information from a JSON, I created a code in php that transforms the database into mySQL into JSON link
I need to get information from a JSON, I created a code in php that transforms the database into mySQL into JSON link
Google suggests volleyball, as far as I can remember. For a very simple application, you can simply use:
import android.util.Log;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.List;
public class HttpRequestHelper {
public static String getRawResult(String url) {
HttpURLConnection c = null;
try {
URL u = new URL(url);
c = (HttpURLConnection) u.openConnection();
c.setRequestMethod("GET");
c.setRequestProperty("Content-length", "0");
c.setUseCaches(false);
c.setAllowUserInteraction(false);
c.setConnectTimeout(40000);
c.setReadTimeout(40000);
c.connect();
int status = c.getResponseCode();
switch (status) {
case 200:
case 201:
BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line+"\n");
}
br.close();
return sb.toString();
}
} catch (MalformedURLException ex) {
Log.i("suaTag", "HttpConnectionHelper error: " + ex.getMessage());
} catch (IOException ex) {
Log.i("suaTag", "HttpConnectionHelper error: " + ex.getMessage());
} finally {
if (c != null) {
try {
c.disconnect();
} catch (Exception ex) {
Log.i("suaTag", "HttpConnectionHelper error: " + ex.getMessage());
}
}
}
return null;
}
}