The problem asks me to count the size of holes in the text exp: A, D, R, O, P has only one hole, and B has two I made the following code:
qnt = int(input())
cont = 0
l = []
for i in range(qnt):
txt = input()
dic = {'A':1, 'D':1, 'O':1, 'P':1, 'R':1, 'B':2}
for i in txt:
if dic.get(i, 0):
cont += dic[i]
print(cont)
However, only the number of holes in the last text appears, and I need each text.
First let's understand why you are only returning the last amount. Considering the code that is here, in the 5 line you have a list named l , but do not use it anywhere else.
In the 7 line you retrieve user input, and do not store it in a list, so the last entry will always be the value of txt .
...
5 l = []
6
7 for i in range(qnt):
8
9 txt = input()
...
I believe that what you were trying to do was add the value of txt in the l
...
5 l = []
6
7 for i in range(qnt):
8
9 txt = input()
10 l.append(txt)
...
If you do this, you would have to change the line 15 :
15 for i in txt:
To:
15 for i in l:
But you can leave it more Pythonic .
dic = {'A':1, 'D':1, 'O':1, 'P':1, 'R':1, 'B':2}
cont = 0
for i in range(int(input())):
txt = input()
if txt in dic: cont += dic[txt]
print(cont)
Example working on repl.it .