Bash, know what directory is running

I do not know if this answers the question further:

#!/bin/bash
echo "A script está em: $0"
echo "O invocador está em $PWD"

Update 1 print the absolute script path

To get the absolute path, we start by joining the current directory with the script directory ( $PWD "=" dirname $0 "/" ).

Then we rewrite (in this case using perl) the cases where q of the script is a relative path ( ./d ../../b b/c ) using overrides.

So:

#!/bin/bash
printf "%s=%s/" $PWD 'dirname $0' |         # formatar como "$PWD=$0/"
    perl -pe 'while(s!/[^/]+=\.\./!=!){};   # a/b=../c --> a=c
              s!.*=/|=\./?!=! ;             # a/b=/c --> =c ;  b=./c => b=c 
              s!=!/!; '

or even

#!/bin/bash
script_dir=$(printf .......e mais as outras 3 linhas... )    
echo $script_dir

Perhaps a more general solution is:

#!/bin/bash
PROGNAME=$(basename $0)
PROGDIR=$(readlink -m $(dirname $0))

This also works for directories with links.