Customize output path of files converted by gulp markdown it

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I was following this step by step , and then there was a need for the markdown files converted to html to be in another folder.

See the code for the file gulpfile.js : 

var gulp = require('gulp');
var markdown = require('gulp-markdown-it');

gulp.task('markdown', function() {
    return gulp.src('**/*.md')
        .pipe(markdown())
        .pipe(gulp.dest(function(f) {
            return f.base;
        }));
});

gulp.task('default', ['markdown'], function() {
    gulp.watch('**/*.md', ['markdown']);
});

Consider the following project structure: 

 meuProjeto
 |_ .vscode
 |  |_ tasks.json
 |_ folder1
 |  |_ fileA.md
 |_ node_modules
 |_ gulpfile.js
 |_ package-lock.json
 |_ sample.md

When I put the task to execute, after some change in the .md files, I get the following result: 

 meuProjeto
 |_ .vscode
 |  |_ tasks.json
 |_ folder1
 |  |_ fileA.html
 |  |_ fileA.md
 |_ node_modules
 |_ gulpfile.js
 |_ package-lock.json
 |_ sample.html
 |_ sample.md

Note that the .html files are together with the original .md files. My goal is to separate them as follows into a build folder: 

 meuProjeto
 |_ .vscode
 |  |_ tasks.json
 |_ build
 |  |_sample.html
 |  |_ folder1
 |     |_ fileA.html
 |_ folder1
 |  |_ fileA.md
 |_ node_modules
 |_ gulpfile.js
 |_ package-lock.json
 |_ sample.md

It would be great if the folders were created automatically.

I tried to change the Gulp task code, but I did not succeed. Is it really possible to do what I want?

    
asked by anonymous 11.06.2018 / 21:08

1 answer

0

Just the gulp.dest function returns the desired folder. You can still specify some folder to ignore: 

gulp.task('markdown', function() {
    return gulp.src(['**/*.md', '!node_modules/**'])
        .pipe(markdown())
        .pipe(gulp.dest('build'));
});
    
11.06.2018 / 22:00
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