With showing the even items of a list in C [closed]

I have a question about this exercise. I tried in several ways but I do not know how to get the position of the pointer to use the content in that case.

• Describe the steps for creating a new element in the list? Develop an algorithm to create an empty chained list. Then create a function that allows you to insert elements into it. Finally, display the even values in the list

#include <stdio.h>
#include <stdlib.h>

typedef struct Lista
{
    int dado;
    struct Lista *prox;

} lista;

lista *insere (lista *prox, int dadoEnviado)
{
    lista *novo;
    novo = (lista *)malloc(sizeof(lista));
    novo->dado = dadoEnviado;
    novo->prox = prox;
    return novo;
}

/*void imprime(lista *pont){

    lista *p;
    for( p = pont; p!=NULL; p=p->prox){
            printf("%d --",p->dado);
    //}

}*/

void imprimePar(lista *l)
{
    lista *p;
    for( p = l; p!=NULL; p=p->prox)
    {
        if( p->dado % 2 == 0)
        {
            printf("%d",p->dado);
        }
    }
}

main()
{
    lista *pont;
    pont = NULL;
    pont = insere(pont, 10);
    pont = insere(pont, 20);
    pont = insere(pont, 30);
    //imprime(pont);
    imprimePar(pont);
}