If I do, good wheel:
#include <stdio.h>
int op1;
int main(){
scanf("%d", &op1);
switch(op1) {
case 1:
puts("Hello World");
}
}
I wanted to make when entering a special character, for example, +, -, / (etc), shows me in the case, "Hello World" instead of having to put 1. Has it like? Something like this:
#include <stdio.h>
int op1;
int main(){
scanf("%d", &op1);
switch(op1) {
case +:
puts("ola");
}
}
This is simply not possible. You can not put what you like in case . Only primitive constant values fit. You can not even use an array , including strings .
What you can use is:
#include <stdio.h>
int main() {
char op1;
scanf("%c", &op1);
switch (op1) {
case '+':
printf("ola");
}
return 0;
}
See running on ideone .
I took the time to organize the code.
I do not know if I understood your question correctly, but if I understood correctly, it is possible.
See the code:
#include <stdio.h>
int main()
{
char op;
scanf(" %c", &op);
switch (op) {
case '+':{printf("Hello World"); break; }
/* outras opções */
}
return 0;
}
In fact it is possible to recognize by char type any character that is in the table ASCII < a>. Take a look, it might just be that. Hope this helps. :)
You can do this:
#include <stdio.h>
char op1;
int main() {
scanf("%c", &op1);
switch(op1) {
case '+': puts("ola");
}
}
Double quotes mean String, single quotes mean Character, so just put single quotes and use a char variable.