How to create an integer variable in hexadecimal?

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How to create an integer variable in hexadecimal?

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#1 by (1 votes)

1

I'm trying to create an integer variable in hexadecimal, but an error occurs saying it is not in the correct format.

[DllImport("user32.dll")]
public static extern short GetKeyState(int vKey);
static void Main(string[] args)
{
    string[] lines = File.ReadAllLines("config.txt");
    int TriggerButton = int.Parse(lines[0].Replace("Trigger Button: ", ""));
    int PanicButton  = int.Parse(lines[1].Replace("Panic Button: ", ""));
    Console.WriteLine(TriggerButton + "\n" + PanicButton);
    while (true)
    {
        Console.WriteLine(GetKeyState(TriggerButton));
    }
    Console.ReadKey();
}

Txt Settings

Trigger Button: 0x12
Panic Button: 0x78

Is there any way to convert a string to a hexadecimal integer without losing 0x ?

c# runtime console

asked by anonymous 06.04.2017 / 12:31

1 answer

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score 1 · Accepted Answer

Without using StringFormat, a valid option is to use

Convert.ToInt32 Method (String, Int32)

Int32 will be the base, in this case 16 Hexadecimal

int PanicButton = Convert.ToInt32(lines[1].Replace("Panic Button: ", ""), 16);

int TriggerButton = Convert.ToInt32(lines[0].Replace("Trigger Button: ", ""), 16);