Where to start putting an ordinal number in a given byte, do I start counting the most significant (left) or least significant (right)?
For example for the decimal number 128 that has the binary representation:
1000 0000
If I want to refer to the eighth byte bit, who is the relevant digit? 1 or 0?
Would it be A-mode or B-mode?
Mode A
1000 0000
8765 4321
Mode B
1000 0000
1234 5678
The A mode would be the correct one.
Ignore the name bit - A binary value is represented in the same way as a decimal value: In an integer the higher value positions are located to the left, since new positions are added when the previous position suffers overflow :
8 + 1 // 9: Uma casa decimal
9 + 1 // 10: Não pode ser contido em apenas uma posição,
10 // casa decimal 2 recebe o valor em overflow.
...
98 + 1 // 99: Duas casas decimais
99 + 1 // 100: Não pode ser contido em apenas duas posições,
100 // casa decimal 3 recebe o valor em overflow.
So:
128 = 100 + 20 + 8
In the above example we can say that the position (house) 3 has the value 1 , which means 100 in decimal.
In binary the value
1000 0000
It has the value 1 in the 8 position, which also means 128 (2 to 7th power).