I am solving a question where I have to do a program that corrects evidence. The program receives a feedback and "n" students responses and compares with the template provided. The answers of all students are put on a single list. My problem is, how to compare the list of answers with the template and print an individual note for each student.
Ex:
gabarito = ['a','b','c','d','e']
resposta_alunos = [['a', 'b', 'c', 'd','d'],['a', 'a', 'c', 'd','d'],...]
I tried to do something as simple as possible. See:
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
respostas = [
['a', 'b', 'c', 'd', 'e'],
['d', 'c', 'c', 'a', 'd'],
['d', 'c', 'd', 'b', 'a'],
['d', 'c', 'c', 'b', 'e']
];
gabarito = ['d', 'c', 'c', 'b', 'e']
for r_num, resposta in enumerate(respostas):
total = 0;
for g_num, valor in enumerate(gabarito):
# Se a posição do valor do gabarito é o mesmo da resposta e os valores iguais
if resposta[g_num] == valor:
#Suponhamos que cada acerto vale 2 pontos
total = total + 2;
print "O aluno %s tirou %d pontos" % (r_num, total)
When running the above code, the result should be:
O aluno 0 tirou 4 pontos
O aluno 1 tirou 6 pontos
O aluno 2 tirou 6 pontos
O aluno 3 tirou 10 pontos
Assuming you have some notion of python , notice that the resposta[g_num] snippet captures through the feedback index the value of one of the responses. This is because, in a template, there is a question number (which would be the index in our case), and therefore should hit both the question number and answer value at the same time.
That's what I got. I do not know if in this case the use of list would be ideal.
Another possibility is to use numpy .
Using the response data from @ wallace-maxters, we can get the number of hits as follows.
import numpy as np
respostas = [
['a', 'b', 'c', 'd', 'e'],
['d', 'c', 'c', 'a', 'd'],
['d', 'c', 'd', 'b', 'a'],
['d', 'c', 'c', 'b', 'e']
];
gabarito = ['d', 'c', 'c', 'b', 'e']
# Transforma em um array
respostas_arr = np.array(respostas)
gabarito_arr = np.array(gabarito)
# Verifica os acertos
verificacao = respostas_arr == gabarito_arr
#[[False False True False True]
# [ True True True False False]
# [ True True False True False]
# [ True True True True True]]
# Soma os acertos
acertos = verificacao.sum(1)
#[2 3 3 5]
# Imprime os resultados
for n, i in enumerate(acertos):
print('O aluno {} acertou {} questões'.format(n+1, i))
#O aluno 1 acertou 2 questões
#O aluno 2 acertou 3 questões
#O aluno 3 acertou 3 questões
#O aluno 4 acertou 5 questões
Compressing everything in one line:
acertos = (np.array(respostas) == np.array(gabarito)).sum(1)
#[2, 3, 3, 5]