5) Make a program that receives the base salary of an employee, calculate and show your salary to receive, knowing that the employee has a bonus of $ 50 and pays 10% tax
#include <stdio.h>
int main()
{
float sal,imposto,s_final;
printf(" CALCULO DE SALARIO \n \n");
printf("Digite seu salario: ");
scanf("%f",&sal);
imposto= sal/100 * 0.1;
s_final = sal-imposto+50;
printf("Salario a receber: %f reais \n",&s_final);
printf("Valor dos impostos: %f reais",&sal);
return 0;
}
O & (and commercial) is used to pass the address of a variable, that is, when you do: printf ("Salary to receive:% f actual \ n", & s_final); printf ("Value of taxes:% f real", & salt);
The printf function is expecting a float, because in the string it has "% f", but "& s; end" represents the address that the value of the variable "s_final" is stored.
To fix this, simply remove & in the printf function call.
Hello I was visualizing your code and the logic is correct, however, you forgot that the "&" is only used for scanf and not for printf (if you use for print it will take the address of the memory and not the content).
I rephrased the code:
#include <stdio.h>
int main()
{
float sal,imposto,s_final;
printf(" CALCULO DE SALARIO \n \n");
printf("Digite seu salario: ");
scanf("%f",&sal);
imposto= (sal*10)/100;
s_final = sal-imposto+50;
printf("Salario a receber: %f reais \n",s_final);
printf("Valor dos impostos: %f reais",sal);
}
I hope I have helped you!