var list =[
[3,4,7,9,4],[3,4,7,9,5],[3,4,7,9,6],[3,4,7,9,7],
[3,4,7,9,8],[3,4,7,9,9],[3,4,8,3,3],[3,4,8,3,4],
[3,4,8,3,5],[3,4,8,3,6],[3,4,8,3,7],[3,4,8,3,8],
[3,4,8,3,9],[3,6,4,6,7],[3,6,4,6,8],[3,6,4,6,9],
[3,6,4,7,3],[3,6,4,7,4],[3,6,4,7,5],[3,6,4,7,6],
[3,6,4,7,7],[3,6,4,7,8],[3,6,4,7,9],[3,6,4,8,3],
[3,6,4,8,4],[3,6,4,8,5],[3,6,4,8,6],[3,6,4,8,7],
[6,7,8,8,7],[6,7,8,8,8],[6,7,8,8,9],[6,7,8,9,3],
[6,7,8,9,4],[6,7,8,9,5],[6,7,8,9,6],[6,7,8,9,7],
[6,7,8,9,8],[6,7,8,9,9],[6,7,9,3,3],[6,7,9,3,4],
[6,7,9,3,5],[6,7,9,3,6],[6,7,9,3,7],[6,7,9,3,8],
[6,7,9,4,5],[6,7,9,4,6],[6,7,9,4,7],[6,7,9,4,8],
[6,7,9,4,9],[6,7,9,5,3],[6,7,9,5,4],[6,7,9,5,5],
[6,7,9,5,6],[6,7,9,5,7],[6,7,9,5,8],[6,7,9,5,9],
]
Ex: the arrays below would all be deleted because they have repeated elements inside
[3,4,7,9,4]
[3,6,4,7,7]
[6,7,9,4,9]
[6,7,9,5,6]
In the cases below the elements are distinct but they are repeated with different positioning in another array, in which case one would be deleted and another would remain unique within the main array
[3,6,4,7,9]
[3,4,7,9,6]
[3,6,4,8,7]
[3,6,4,7,8]