Use your index file listanome.txt to make a script to be used by sed to remove rows:
For a listanome.txt as below ...
$ cat listanome.txt
ze
jao
juca
... the following sed transforms into an exclude script for each name in the list:
$ sed 's/^/\//; s/$/\/d/' listanome.txt
/ze/d
/jao/d
/juca/d
So, pass this command sed to the -f flag of a new sed , which will execute that script on all files to be affected, supposedly contained in the caminho directory:
$ sed --in-place=.bak -f <(sed 's/^/\//; s/$/\/d/' listanome.txt) /caminho/*
This will delete all rows from all files in the caminho directory containing names of listanome.txt , making backups with the extension ".bak "for each changed file.
If your requirement changes, change the first sed according to what you want, for example:
To delete all lines identical to the index:
$ sed 's/^/\/^/; s/$/$\/d/' listanome.txt
/^ze$/d
/^jao$/d
/^juca$/d
To replace the contents of the string with the "REMOVE" string:
$ sed 's/^/\/^\.\*/; s/$/\.\*$\/REMOVER\/g/' listanome.txt
/^.*ze.*$/REMOVER/g
/^.*jao.*$/REMOVER/g
/^.*juca.*$/REMOVER/g
You can use xargs to accomplish the task you want, here's an example where I've ready a directory and get all the .cfg files and insert a line into the found files:
ls *.cfg | xargs sed -i"23i#####################################################"
understanding the above command better:
ls *.cfg - > lists all files that end with the extension .cfg
| xargs - > takes the data that was displayed in the previous command to apply the following command.
sed -i"23i#####################################################" - > inserts a line in each file found in the command ls , in which case I am inserting in line 23 of each file.
I believe that in your need the ideal would be to create a for you to read each line of your first file and after that apply the necessary action.