Would it be the right one?
<?php
dateTime();
?>
By searching for Google, I still have not found a valid answer.
Would it be the right one?
<?php
dateTime();
?>
By searching for Google, I still have not found a valid answer.
Using the time () strtotime () functions and comparing the dates, you can do the following:
class Data {
public static function ExibirTempoDecorrido($date)
{
if(empty($date))
{
return "Informe a data";
}
$periodos = array("segundo", "minuto", "hora", "dia", "semana", "mês", "ano", "década");
$duracao = array("60","60","24","7","4.35","12","10");
$agora = time();
$unix_data = strtotime($date);
// check validity of date
if(empty($unix_data))
{
return "Bad date";
}
// is it future date or past date
if($agora > $unix_data)
{
$diferenca = $agora - $unix_data;
$tempo = "atrás";
}
else
{
$diferenca = $unix_data - $agora;
$tempo = "agora";
}
for($j = 0; $diferenca >= $duracao[$j] && $j < count($duracao)-1; $j++)
{
$diferenca /= $duracao[$j];
}
$diferenca = round($diferenca);
if($diferenca != 1)
{
$periodos[$j].= "s";
}
return "$diferenca $periodos[$j] {$tempo}";
}
}
Calling the function:
print_r(Data::ExibirTempoDecorrido(date("12/31/2010")));
You'll get the result:
3 anos atrás