Calendar in PHP

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Calendar in PHP

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#1 by (2 votes)
#2 by (0 votes)

1

I have a calendar in php and I would like to know two things!

How do I get the date started on Monday? (Day 1 second, for example), and how to make Sundays appear in red.

Here is the code:

<!DOCTYPE HTML>
<html lang="pt-br">
<head>
    <meta charset="UTF-8">
    <title>Calendário em PHP</title>
    <?php 
        date_default_timezone_set('America/Sao_Paulo');
    ?>
</head>
<body>
    <h1>Estamos em <?php echo date('Y');?></h1>
        <p>Hoje é dia <strong><?php echo date('d / '); ?></strong>
            <?php echo date('m'); ?>
            agora são <?php echo date ('H'); ?>horas e
            <?php echo date('i');?> minutos.</p>

        <?php
            function linha($semana){
                echo "<tr>";
                for ($i = 0; $i <=6; $i++){
                    if(isset($semana[$i])){
                        echo "<td>{$semana[$i]}</td>";
                    } else{
                        echo "<td></td>";
                    }
                }
                echo "</tr>";
            }
            function calendario(){
                $dia = 1;
                $semana = array();

                while($dia <= 31){
                    array_push($semana, $dia);
                    if(count($semana) == 7){
                        linha($semana);
                        $semana = array();
                    }
                    $dia++;
                }
                linha($semana);
            }
        ?>
        <table border="1">
            <tr>
                <th>Dom</th>
                <th>Seg</th>
                <th>Ter</th>
                <th>Qua</th>
                <th>Qui</th>
                <th>Sex</th>
                <th>Sáb</th>
                <?php calendario(); ?>
            </tr>
        </table>
</body>
</html>

php

asked by anonymous 11.10.2014 / 01:00

2 answers

App rejected because of the Advertising Identifier (IDFA) Save text of a tkinter Text object to a variable

score 2 · Answer 1

Try it out:

<!DOCTYPE HTML>
<html lang="pt-br">
<head>
    <meta charset="UTF-8">
    <title>Calendário em PHP</title>
    <?php 
        date_default_timezone_set('America/Sao_Paulo');

        $hoje = getdate(strtotime($_GET['t']));

        $ultimoDia = cal_days_in_month(CAL_GREGORIAN,
                                       $hoje['mon'],
                                       $hoje['year']);

        $primeiraSemana = (($hoje['wday'] + 1) -
                          ($hoje['mday'] - ((int)($hoje['mday'] / 6) * 7))) % 7;
        // Alternativa:
        /*$primeiroDiaTimestamp = strtotime(sprintf("%d-%0d-01",
                                                  $hoje['year'],
                                                  $hoje['mon']));
        $primeiraSemana = (int)date('w', $primeiroDiaTimestamp);*/
    ?>

    <style>
        td[data-semana="0"] { color: #ff0000; }
    </style>
</head>
<body>
    <h1>Estamos em <?= $hoje['year'] ?></h1>
    <p><?= sprintf('Hoje é dia <strong>%0d / %0d</strong>, agora são %02d horas e %0d minutos.',
                   $hoje['mday'], $hoje['mon'], $hoje['hours'], $hoje['minutes'])
    ?></p>

    <table border="1">
        <tr>
            <th>Dom</th>
            <th>Seg</th>
            <th>Ter</th>
            <th>Qua</th>
            <th>Qui</th>
            <th>Sex</th>
            <th>Sáb</th>
        </tr>
        <tr>
        <?php
        for($semana = 0; $semana < $primeiraSemana; ++$semana) {
            echo '<td>&nbsp;</td>';
        }
        for($dia = 1; $dia < $ultimoDia; ++$dia) {
            if( $semana > 6 ) {
                $semana = 0;
                echo '</tr><tr>';
            }

            echo "<td data-semana=\"$semana\">";
            echo "$dia</td>";
            ++$semana;
        }
        for(; $semana < 7; ++$semana) {
            echo '<td>&nbsp;</td>';
        }
        ?>
        </tr>
    </table>
</body>
</html>

I've put the CSS style in HTML, but it's good practice to put another CSS-only file.

I used the cal_days_in_month function to have the last day of the month.

To find out what day of the week, I showed you two solutions:

using the strtotime function to get the timestamp of the first day of the month, which can then be used in the date
doing an arithmetic calculation (I suppose the performance is better - it does not invoke two complex functions):
count the completed weekdays that have passed to date: (int)($hoje['mday'] / 6 ;
subtract today by the days of the complete weeks counted, giving the remaining days: $hoje['mday'] - ((int)($hoje['mday'] / 6) * 7)
subtract the number of the weekday plus one (Sunday is 0, second is 1, ...) for the previous result: ($hoje['wday'] + 1) - ($hoje['mday'] - ((int)($hoje['mday'] / 6) * 7))

For example, today is day 11 and Saturday. Only a full week passed (11/6 = 1.6 ...). One week has 7 days (1 * 7 = 7). It was 4 days after the 7 days (11 - 7 = 4). If the first day of the week was Sunday, a week or four more days would be spent on a Wednesday. It is necessary to pull the days to Saturday (7 days): 7 - 4 = 3 (a Wednesday).

The rest is easy:

lets pass the days that are not shown in the calendar.

shows the days of the month indicating the day of the week in the element "td"; when it is Saturday, the line ends (I assume you are using HTML5, which allows data-* attributes).

Finally, skip the remaining days until the end of the week (Saturday).

score 0 · Answer 2

function linha($semana){
    $dias = count($semana);
    echo "<tr>";
    for ($i = 1; $i < $dias; $i++){
        if(isset($semana[$i])){
            echo "<td>{$semana[$i]}</td>";
        } else{
            echo "<td></td>";
        }
    }
    echo "<td class="vermelho">{$semana[0]}</td>";
    echo "</tr>";   }

Complementing my previous comment, it would be something like this. I did not test the code because it is simple to implement, if you have something wrong you give a set, which is very simple.