If it is executed even with the condition being false

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#1 by (16 votes)

6

I have an excerpt of a function with the following code:

printf("caminho: %d\n", t);
printf("min: %d\n", min);
if( min >= t && t != -1);
{
    printf("oi\n");
    min = t;
    printf("min: %d\n",min);
}

and as a result I have:

path: 2

min: 1

oi

min: 2

The line that prints "hi" is executed, even with the conditional being false.

Can anyone tell me how this can happen?

c

asked by anonymous 04.04.2016 / 21:07

1 answer

score 16 · Accepted Answer

You have a semicolon in front of the condition of your if :

if( min >= t && t != -1);

Regardless of the outcome, nothing will happen.

Then you have a loose block:

{
    printf("oi\n");    
    min = t;
    printf("min: %d\n",min);
}

It will run anyway.