I'm currently trying to establish a comparison of two vectors in C.
My code structure is as follows:
int iguais(int *v1, int *v2, int tam) {
int i, cont = 1;
for(i=0; i<tam; i++) {
while(*(v1 + i) == *(v2 + i)) {
cont++;
}
}
return (cont == tam);
}
Can anyone help me in the debugging process?
You do not need two ties. If both arrays are the same size, just check element-by-element if v1[i] == v2[i] (the pointer syntax is equivalent).
As optimization, instead of counting the amount of equal elements, it is worth checking if there is a different element ( v1[i] != v2[i] ), returning false immediately and avoiding extra iterations:
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
bool iguais(int *v1, int *v2, int tam) {
int i, cont = 1;
for(i=0; i < tam; i++) {
if (v1[i] != v2[i]) {
return false;
}
}
return true;
}
int main() {
int v1[] = {1, 2, 3, 4, 5};
int v2[] = {1, 2, 3, 4, 5};
int v3[] = {1, 2, 3, 4, 6};
printf("v1 e v2 sao %s\n", iguais(v1, v2, 5) ? "iguais" : "diferentes");
printf("v1 e v3 sao %s\n", iguais(v1, v3, 5) ? "iguais" : "diferentes");
return 0;
}