How to get link from any anchor, using regular expression?

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1

I use this code to capture links from a particular page: 

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);    
$resultado = curl_exec($ch);

preg_match_all('/<a href="/(.*)"/i', $resultado, $outros);

However, this regular expression leaves out links such as: 

<a name="exemplo" href="link.php"></a>

And if I take out <a and leave only href for example: 

preg_match_all('/href="/(.*)"/i', $resultado, $outros);

There you will get undue stuff like css links for example: 

<link href="link.css">

What is the ideal regular expression for capturing all href of elements a without the risk of capturing href of elements that are not a , such as css for example?     

asked by anonymous 19.01.2017 / 03:29

1 answer

2

Try this way, ignoring what is between a and href : 

preg_match_all('/<a.*href="(.*)"/i', $resultado, $outros);

I hope I have helped!

    
19.01.2017 / 03:50
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