I have a regex that is valid as per the test link , but in the vi it does not work:
2017\/04\/26 12:24:(.*)(89418644)
Here is an example that this REGEX should get married:
INFO | 2017/04/26 12: 24: 15,019 | [OrderEntryAvailableOutgoingFlowListPopulator] 89418644 OK
I think it's some syntax rule for using groups in vi search, but I still can not identify.
When you perform a search on vi it does not interpret directly that what you are using is a REGEX, so that what it actually searches for is String .
So you should use the same log when passing a String to REGEX, and you need to escape the special characters.
2017\/04\/26 12:24:\(.*\)\(89418644\)
If you are just searching you could simply remove the groups:
2017\/04\/26 12:24:.*89418644
If you are working with replace with a modifier that assists in this \v :
:%s/\v2017\/04\/26 12:24:(.*)(89418644)/REPLACE/
Source Vim Regex Capture Groups