I have a string with several words inside, some words are separated by space, but some are compound words and are protected by brackets.
EX:
string="Goiânia Vitória Brasília [Campo Grande] Fortaleza [São Paulo] Manaus"
I need to separate these words by returning a list with them separated.
Output EX:
"Goiânia"
"Victory"
"Brasilia"
"Big Field"
"Fortress"
"São Paulo"
"Manaus"
How do I create a regular expression that does this in python?
Well, the idea is basically to work with groupings.
The first step is to identify the data pattern to mount the appropriate regex.
Based on the information provided, I have identified the following pattern:
\[(.*?)\]|(\S+)
Basically it is any grouping between [], or (|) any grouping of words.
You can test regex in real time on the Rubular ,
This regex will basically return you in case of match in group 1 the names between [], and in group 2 the other words.
Using the python3 programming language would look something like:
import re
text = """Goiânia Vitória Brasília [Campo Grande] Fortaleza [São Paulo] Manaus [Santa Bárbara d'Oeste]"""
regex = re.compile('\[(.*?)\]|(\S+)')
matches = regex.finditer(text)
for match in matches:
if(match.group(1) is None):
print(match.group(2))
else:
print(match.group(1))
See working at Ideone