I want to make a shell script that receives a filename with its full path, for example /home/42/arquivoEscolhido.txt , and extract only the file name ( arquivoEscolhido.txt ), which would be everything after the last slash ( / ), taking into account that the file name can always change.
I came up with something like this but it did not work:
echo -n 'Informe o arquivo: '
read dir #/home/42/teste.txt
arq=${dir#*/}
Just missing one: arq=${dir##*/} will be teste.txt
${var#padrão} will remove only until the first occurrence of the pattern.
${var##padrão} will remove until the last occurrence of the pattern.
Since this is a file path, another option is to use the basename command:
basename /home/42/teste.txt
The output is:
teste.txt
Inside a script, just run the command with command substitution syntax by placing it between $( ) :
echo -n 'Informe o arquivo: '
read dir #/home/42/teste.txt
# executa o comando basename, a saída é colocada na variável arq
arq=$(basename $dir)
So, if the file path is /home/42/teste.txt , the variable arq will have the value teste.txt .
According to documentation :
strip directory and suffix from filenames
Free translation:
remove directory and suffix of filenames
That is, you can also pass as a parameter the suffix to be removed. With this, you can also remove the file extension, for example:
basename /home/42/teste.txt .txt
Output:
teste