Build an unordered list with content_tag

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How to build a list containing sublists using content_tag f% of Rails?

Using the method in Helper does not work. 

<ul class="menu">
 <li>Item1
  <ul>
   <li><a href="#>Link1</a></li>
   <li><a href="#>Link2</a></li>
   <li><a href="#">#
asked by anonymous 14.01.2015 / 19:02

2 answers

2

With this code you can create the list: 

def li_with_link(link_text, link_url)
  content_tag :li, link_to(link_text, link_url)
end

def ul_with_lis
  content_tag :ul, class: 'menu' do
    content_tag :li do
      "Item1" + li_with_link("link1", '#') + li_with_link("link2", '#')
    end
  end
end

Note: If your idea is to simplify, better use ERB!

Take a look at the method documentation as well: link

    
14.01.2015 / 19:25
1

This Rodrigo tip has a problem: each link will have a UL + LI, but I agree with it that using ERB (or HAML, or SLIM) is better. If for some reason you need to do this with ruby, maybe this will help: 

def menu(links = [])
  content_tag :ul do
    links.map do |link|
      content_tag :li do
        link_to link[:label], link[:href]
      end
    end
  end
end

call: 

<% links = [] %>
<% links << { label: 'google', href: 'https://google.com' } %>
<% links << { label: 'facebook', href: 'https://facebook.com' } %>
<% links << { label: 'twitter', href: 'https://twitter.com' } %>
<% links << { label: 'logout', href: logout_path %>
<%= menu(links) %>
    
14.01.2015 / 23:37
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