I have the following line
echo date('Y-m-d', strtotime("28/09/2016")); // 1970-01-01
How do I get back 2016-09-28? If the day is less than 12, it returns true ...
Return correct date strtotime php
1
asked by anonymous 17.08.2016 / 15:23
2 answers
2
You need to pass as a parameter to strtotime a string with separator using - (hyphen) for example;
$date = str_replace("/", "-", "28/09/2016");
echo date("Y-m-d", strtotime($date));
17.08.2016 / 15:43
1
You can do this using the DateTime object of PHP:
$formato = 'd/m/Y'; // define o formato de entrada para dd/mm/yyyy
$data = DateTime::createFromFormat($formato, "28/09/2016"); // define data desejada
echo $data->format('Y-m-d'); // formata a saída
Read more about the supported formats in PHP - DATE
17.08.2016 / 15:46