JSON Openload PHP

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JSON Openload PHP

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#1 by (3 votes)
#2 by (0 votes)

1

Can anyone help me? I have the following url json: link

I would like to know how to list in php every part that has json left type

Name: the name you have in json Id: id that has json

And for a json like this:

{"status":200,"msg":"OK","result":{"ticket":"valorticket","captcha_url":"valorcaptcha","captcha_w":160,"captcha_h":70,"wait_time":0,"valid_until":"2018-05-11 15:55:44"}}

How would the code look? I have a url with json from the way, I tried changing the url and not the result, only errors

php json

asked by anonymous 11.05.2018 / 15:18

2 answers

List C # losing what has already been added Laravel - Validate field unique in update

score 3 · Answer 1

Using curl or file_get_contents and then using json_decode .

The result of this:

{"status":200,"msg":"OK","result":{"6PHaY9bqRYc":{"id":"6PHaY9bqRYc","status":200,"name":"big_buck_bunny_720p_1mb.mp4","size":"1055726","sha1":"5b4395dabecd6308ec82bb4f1626f41c40e64654","content_type":"video\/mp4","cstatus":"1"}}}

With json_decode will be more or less these:

Array
(
    [status] => 200
    [msg] => OK
    [result] => Array
        (
            [6PHaY9bqRYc] => Array
                (
                    [id] => 6PHaY9bqRYc
                    [status] => 200
                    [name] => big_buck_bunny_720p_1mb.mp4
                    [size] => 1055726
                    [sha1] => 5b4395dabecd6308ec82bb4f1626f41c40e64654
                    [content_type] => video/mp4
                    [cstatus] => 1
                )

        )

)

Then you will have to use a foreach also, for example:

<?php

$response = file_get_contents('https://api.openload.co/1/file/info?file=6PHaY9bqRYc');

if (!$response) {
   die('Erro nos dados');
}

$data = json_decode($response, true);

if ($data['status'] != 200) {
   die('Erro HTTP:' . $data['status']);
}

foreach ($data['result'] as $id => $details) {
    echo 'id: ', $details['id'], '<br>';
    echo 'Nome: ', $details['name'], '<br>';
    echo 'Tamanho: ', $details['size'], '<br>';
    echo 'Content-Type: ', $details['content_type'], '<hr>';
}

From the other JSON:

{"status":200,"msg":"OK","result":{"ticket":"valorticket","captcha_url":"valorcaptcha","captcha_w":160,"captcha_h":70,"wait_time":0,"valid_until":"2018-05-11 15:55:44"}}

It should look like this:

<?php

//Esta em string, mas suponho que venha de uma URL
$response = '{"status":200,"msg":"OK","result":{"ticket":"valorticket","captcha_url":"valorcaptcha","captcha_w":160,"captcha_h":70,"wait_time":0,"valid_until":"2018-05-11 15:55:44"}}';

if (!$response) {
   die('Erro nos dados');
}

$data = json_decode($response, true);

if ($data['status'] != 200) {
   die('Erro HTTP:' . $data['status']);
}

$result = $data['result'];

print_r($result);

echo 'ticket: ', $result['ticket'], PHP_EOL;
echo 'URL captcha: ', $result['captcha_url'], PHP_EOL;
echo 'Largura captcha: ', $result['captcha_w'], PHP_EOL;
echo 'Largura altura: ', $result['captcha_h'], PHP_EOL;
echo 'Validade: ', $result['valid_until'], PHP_EOL;

It does not need foreach because result only receives "one object", while the other json received in result: an object with variant key, for example "6PHaY9bqRYc": and was still "multi-dimensional".

score 0 · Answer 2

Using file_get_contens() and json_decode :

<?php
    $json=file_get_contents('https://api.openload.co/1/file/info?file=6PHaY9bqRYc');
    $json=json_decode($json);
    echo 'Status: '.$json->status;
?>

Function reference file_get_contents ()
p>
Function reference json_decode ()