int[] numeros = new int[] {text_box1, text_box2, text_box3, text_box4};
int[] pares = new int[] {02, 04, 06, 08, 10};
int[] impares = new int[] {01, 03, 05, 07, 09};
int[] numeros = new int[] {text_box1, text_box2, text_box3, text_box4};
int[] pares = new int[] {02, 04, 06, 08, 10};
int[] impares = new int[] {01, 03, 05, 07, 09};
Following strictly the arrays of your question you can use Intersect
of Linq:
int[] numeros = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
int[] pares = new int[] { 02, 04, 06, 08, 10 };
int[] impares = new int[] { 01, 03, 05, 07, 09 };
int[] inputsPares = numeros.Intersect(pares).ToArray();
int[] inputsImpares = numeros.Intersect(impares).ToArray();
int quantosPares = inputsPares.Length;
int quantosImpares = inputsImpares.Length;
For the problem in question, which is just checking whether it is even or odd, you can use the mod operator, so you do not need the arrays pares
and impares
.
int[] inputsPares = numeros.Where(x => x % 2 == 0).ToArray();
int[] inputsImpares = numeros.Where(x => x % 2 != 0).ToArray();