I have the following code, to look up a certain numbering and check if it exists. In the STR variable, text with numbers is sent.
function verifica(str) {
if (str.match = '/\d\d\d\d\d\.\d\d\d\d\d') {
var old = str.match(/\d\d\d\d\d\.\d\d\d\d\d/);
result = 1;
}
else if (str.match = '/\d\d\d\d\d\.\d\d\d') {
var old = str.match(/\d\d\d\d\d\.\d\d\d/);
result = 2;
} }
He is not respecting these rules, he only respects the if, the else IF does not respect. What could be wrong?
There are two problems with your code.
The first problem is that when you want to compare two variables you must use == , or === . What you use is a = assignment, and this compares nothing. Using only = will make the left variable stay with the value that is on the right. Actually when using = you are rewriting the .match() function. That is, .match() is assigned the value that it assigns and stops working ...
The second problem is how to use .match() . I assume you want to use if in case str has a certain set of characters. Then just use something like str.match(/[1-2]/) . This in itself already returns what you need to use in if. For example:
var str = '1233';
str.match(/[1-2]/); // dá verdadeiro no if, mais exatamente ["1"]
str.match(/[1-2]/g); // dá verdadeiro, mais exatamente ["1", "2"] pois usa o "g" no match que retorna não só o primeiro encontrado
So what you should use is only:
if (str.match(/\d\d\d\d\d\.\d\d\d\d\d/)) {
Since you want to assign a new value to the variable old , and remembering that an attribute with = returns a value if you do not use var then your code could be :
function verifica(str) {
var old;
if (old = str.match(/\d\d\d\d\d\.\d\d\d\d\d/)) {
result = 1;
} else if (old = str.match(/\d\d\d\d\d\.\d\d\d/)) {
result = 2;
}
return result; // isto acrescentei eu, para a função retornar um valor
}