Validation of CNPJ in Javascript

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Validation of CNPJ in Javascript

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#1 by (4 votes)

1

I have a simple question. I want to validate the cnpj of an institution register. In this input is already placed the mask, in which the mask is in js. But I can not validate this field. I took a famous example of the net, but it is not working when I put in the input, does anyone know the right code?

Note: I'm using angular

function FormataCnpj(campo, teclapres)
			{
				var tecla = teclapres.keyCode;
				var vr = new String(campo.value);
				vr = vr.replace(".", "");
				vr = vr.replace("/", "");
				vr = vr.replace("-", "");
				tam = vr.length + 1;
				if (tecla != 14)
				{
					if (tam == 3)
						campo.value = vr.substr(0, 2) + '.';
					if (tam == 6)
						campo.value = vr.substr(0, 2) + '.' + vr.substr(2, 5) + '.';
					if (tam == 10)
						campo.value = vr.substr(0, 2) + '.' + vr.substr(2, 3) + '.' + vr.substr(6, 3) + '/';
					if (tam == 15)
						campo.value = vr.substr(0, 2) + '.' + vr.substr(2, 3) + '.' + vr.substr(6, 3) + '/' + vr.substr(9, 4) + '-' + vr.substr(13, 2);
				}
			}



function validarCNPJ(cnpj) {
 
    cnpj = cnpj.replace(/[^\d]+/g,'');
 
    if(cnpj == '') return false;
     
    if (cnpj.length != 14)
        return false;
 
    // Elimina CNPJs invalidos conhecidos
    if (cnpj == "00000000000000" || 
        cnpj == "11111111111111" || 
        cnpj == "22222222222222" || 
        cnpj == "33333333333333" || 
        cnpj == "44444444444444" || 
        cnpj == "55555555555555" || 
        cnpj == "66666666666666" || 
        cnpj == "77777777777777" || 
        cnpj == "88888888888888" || 
        cnpj == "99999999999999")
        return false;
         
    // Valida DVs
    tamanho = cnpj.length - 2
    numeros = cnpj.substring(0,tamanho);
    digitos = cnpj.substring(tamanho);
    soma = 0;
    pos = tamanho - 7;
    for (i = tamanho; i >= 1; i--) {
      soma += numeros.charAt(tamanho - i) * pos--;
      if (pos < 2)
            pos = 9;
    }
    resultado = soma % 11 < 2 ? 0 : 11 - soma % 11;
    if (resultado != digitos.charAt(0))
        return false;
         
    tamanho = tamanho + 1;
    numeros = cnpj.substring(0,tamanho);
    soma = 0;
    pos = tamanho - 7;
    for (i = tamanho; i >= 1; i--) {
      soma += numeros.charAt(tamanho - i) * pos--;
      if (pos < 2)
            pos = 9;
    }
    resultado = soma % 11 < 2 ? 0 : 11 - soma % 11;
    if (resultado != digitos.charAt(1))
          return false;
           
    return true;
    
}

 <input type="text" name="cnpj" id="cnpj" onkeyup="FormataCnpj(this,event)" maxlength="18"  class="form-control input-md" ng-model="cadastro.cnpj" required>

javascript html angularjs input

asked by anonymous 31.05.2016 / 20:01

1 answer

Catch the data inside a result json_decode A comparison between 2 char (s) is wrong

score 4 · Accepted Answer

Put the onblur so that when it leaves the field it validates for you.

Follow the example below of how you would do in your input.

 <input type="text" name="cnpj" id="cnpj" onkeyup="FormataCnpj(this,event)" onblur="if(!validarCNPJ(this.value)){alert('CNPJ Informado é inválido'); this.value='';}" maxlength="18"  class="form-control input-md" ng-model="cadastro.cnpj" required>