I want to remove numbers in the middle of letters, but I do not want to remove all numbers from the text, for example:
Vini12cius
I want to transform to Vinicius , but without changing a possible CPF that will come after, I created the following regex:
r = re.sub(r'([0-9])','',"")
However, it deletes all text numbers, even those that are not between characters, I also tried:
r = re.sub(r'([a-z]*[0-9]*[a-z])','',"")
But I did not succeed either.
I'd rather do this with a replacement function:
>>> def f(m):
... text = m.group()
... if text.isdigit(): # se for tudo digito
... return text
... else:
... return re.sub(r'\d', '', text)
...
>>> re.sub(r'\w+', f, '4lfr3do rodr1g0 marc05 12345')
'lfrdo rodrg marc 12345'
You can use this Regular Expression: \d+(?=[a-zA-Z]+)|(?<=[a-zA-Z])\d+
Where the demo of Regex101 can be seen.
import re
testes = ("Vini12cius 000.000.000-00",
"Vini12cius 00000000000",
"Vinicius12 00000000000",
"12Vinicius 00000000000",
"000.000.000-00 Vini12cius",
"00000000000 Vini12cius",
"00000000000 Vinicius12",
"00000000000 12Vinicius")
padrao_regex = re.compile(r"\d+(?=[a-zA-Z]+)|(?<=[a-zA-Z])\d+")
substituicoes = [re.sub(padrao_regex, "", elemento_teste) for elemento_teste in testes]
if substituicoes:
for substituicao in substituicoes:
print(substituicao)