I'm trying to build a regular expression and it's a bit difficult.
I would like you to help me, and if possible explain how the computer works in relation to this expression I am asking.
I need to get everything at the beginning of a String, until a group of Strings is found, for example:
I want to get from the beginning of the String until it is found "2.8" or "6v" or "2p".
Thank you.
/^(.)+(?=([\d+]\.?[\d+]|\d\w))/g
^(.)+
(?=
(
[\d+]\.?[\d+]
|
\d\w
)
)
This expression will get any text that comes before "0.0" or "0x".
Explanation of the expression:
^(.)+ any text since the beginning of the string (?=) text must be followed by the following expression: [\d+]\.?[\d+] digit point digit, or ... \d\w digit and one letter /((^[\s\S]+)2\.8)|((^[\s\S]+)6v)|((^[\s\S]+)2p)/g
Explaining:
[\s\S] takes everything.
+ takes all the characters that satisfy the previous condition, therefore "everything of everything".
^ indicates the beginning of the String, so I put it before fetching "all".
After that, just place where you want the search to stop. The parentheses are for organization purposes, to leave everything apart.
| is an "or" operator. I just put the same code 3 times, changing only the stop condition.
\. is to search for the point. I had forgotten to add but I edited.
Here's an example: link