I have the following regular expression ' ((?:[\d][\s]?){5}[\d]) ' and I'm testing it on link .
My problem is this: If I have this snippet ' teste 123456 teste ' it will only return me ' 123456 ' which is correct. But if it is ' teste 12 345 6 teste ' it returns me ' 12 345 6 '.
I would like to know a way for it to return only the numbers without the spaces, if it has spaces.
"teste 123456 teste".replace(/\D/g, ''); // 123456
"teste 12 345 6 teste".replace(/\D/g, ''); // 123456
var input = "teste 12 345 6 teste"; // string teste
var regex = /(\d+)| /g; // regex
var matches, output = []; // vars para processo
while (matches = regex.exec(input)) { // captura do contudo, o exec vai capturar
// o primeiro resultado que encontrar seja
// '\d' ou ' ', quando capturar ' ' não
// haverá grupo 1, assim ao fazer o 'matches[1]'
// este estará 'undefined' que no filter é
// false, assim o eliminando do array.
output.push(matches[1]); // adiciona o grupo 1 a out
}
output.filter(function(value){
return value; // limpeza do array
}).join('') // concatena tudo por join
Result: 123456
If it is exactly for that expression that says in the comment, do so it gives. If you do not boot the possible variables, which agent hits ...
"(\b[0-9]\b)/g"
If it is enough of the ok in the answer, if no one comments that agent hits ...
Regular expressions are used to recognize characters within a string. With them you can also get what was the recognized substring.
It occurs that 123456 is not substring of teste 12 345 6 teste . And therefore, you will not be able to get 123456 as a response using only regex in a single step because 123456 is not exactly like this in the input string.
Then you do the following:
((?:[\d][\s]?){5}[\d]) to find the number with spaces. replace .